# 3483 A Very Simple Problem 数论+矩阵的应用

看着别人的解题报告写的，推导过程还是不太懂 求sum(x^&#x6B;_&#x6B;^x) k=1\~N x^(k+1)_(k+1)^x=x^&#x6B;_&#x78;_(k+1)^x 然后用二项式定理展开(k+1)^x即可 例如当x=4时\
\| 1x 0 0 0 0 0 | |x^&#x6B;_&#x6B;^0| |x^(k+1)_(k+1)^0| | 1x 1x 0 0 0 0 | |x^&#x6B;_&#x6B;^1| |x^(k+1)_(k+1)^1| | 1x 2x 1x 0 0 0 |_|x^&#x6B;_&#x6B;^2|=|x^(k+1)_(k+1)^2| | 1x 3x 3x 1x 0 0 | |x^&#x6B;_&#x6B;^3| |x^(k+1)_(k+1)^3| | 1x 4x 6x 4x 1x 0 | |x^&#x6B;_&#x6B;^4| |x^(k+1)\*(k+1)^4| | 1x 4x 6x 4x 1x 1x | | S(k) | | S(k+1) |
